$\mathrm{The} \mathrm{volume} \mathrm{of} \mathrm{the} \mathrm{solid} \mathrm{generated} \mathrm{by} \mathrm{revolving} \mathrm{the} \mathrm{region} \mathrm{between} \mathrm{the} \mathrm{Y}-\mathrm{axis} \mathrm{and} \mathrm{the} \mathrm{curve} \mathrm{x}=2\sqrt{\mathrm{y}}, 0 \le \mathrm{y} \le 4, \mathrm{about} \mathrm{the} \mathrm{Y}-\mathrm{axis}.$

If curve $\mathrm{y}=\mathrm{f}\left(\mathrm{x}\right)$ is revolve about $\mathrm{x}$ - axis from $\mathrm{x}=\mathrm{a}$ to $\mathrm{x}=\mathrm{b}$ , then the area of surface of a solid is _____.

The plane area bounded by curves $\mathrm{y}=\mathrm{a}, \mathrm{y}=\mathrm{b}, \mathrm{x}=\mathrm{f}\left(\mathrm{y}\right), \mathrm{x}=\mathrm{g}\left(\mathrm{y}\right)$ is revolved about Y-axis to generate the solid. The volume of solid is _____.