MCQs of Power System Matrices (Interconnected Power System - 2170901)

Interconnected Power System (2170901) MCQs

MCQs of Power System Matrices

Showing 11 to 20 out of 30 Questions

11.

The dimention of bus incidance matrix is (b=no. of branchs, n=no. of nodes)

(a)	b x (n-1)
(b)	b x 2n
(c)	n x b
(d)	2n x b

12.

Primitive network is

(a)	A sets of individual elements of power system
(b)	A set of coupled elements which gives information regarding the characteristics of individual elements only
(c)	A set of uncoupled elements which gives information regarding the characteristics of individual elements only
(d)	None of above

13.

The performance equations of any branch ‘i’ in impedance form will be'

(a)	$V_{i} + e_{i} = Z_{i} \times I_{i}$
(b)	$V_{i} = Z_{i} \times I_{i}$
(c)	$V_{i} - e_{i} = Z_{i}$
(d)	$V_{i} - e_{i} = Z_{i} \times I_{i}$

14.

The performance equations of any branch ‘i’ in admitance form will be

(a)	$I_{i} = y_{i} \times V_{i}$
(b)	$i_{i} + j_{i} = y_{i} \times v_{i}$
(c)	$i_{i} - j_{i} = y_{i}$
(d)	None of above

15.

The matrix [Z] and [Y] is diagonal if

(a)	There is a mutual coupling between elements
(b)	There is no mutual coupling between elements
(c)	Power system is not real
(d)	Power system is in fault

16.

In direct inspection method, the equation of first diagonal element of $Y_{b u s}$ for 3 bus system is

(a)	$Y_{11} = y_{11} + y_{12} + y_{13}$
(b)	$Y_{22} = - y_{22}$
(c)	$Y_{33} = y_{13} + y_{23} + y_{33}$
(d)	$Y_{22} = y_{12} + y_{22} + y_{23}$

17.

In direct inspection method, the element $Y_{12}$ is

(a)	$- y_{13}$
(b)	$- y_{12}$
(c)	$y_{11} + y_{12}$
(d)	None of above

18.

The diagonal term in $Y_{b u s}$ is

(a)	Mutual admitance
(b)	Self admitance
(c)	Both Self and mutual admitance
(d)	None of above

19.

According to singular transformation method, the equation of $Y_{b u s}$ is

(a)	$A^{T} [y]$
(b)	$A^{T} A$
(c)	$A^{T} [y] A$
(d)	None of above

20.

If $A = [\begin{matrix} - 1 & 0 & 0 & 1 \\ 0 & - 1 & 1 & 0 \\ 0 & 0 & - 1 & - 1 \end{matrix}]$ and $Z_{p r i m i t i v e} = [\begin{matrix} j 0.5 & j 0.1 & 0 & 0 \\ j 0.1 & j 0.6 & 0 & 0 \\ 0 & 0 & j 0.4 & 0 \\ 0 & 0 & 0 & j 0.3 \end{matrix}]$ , then $Y_{b u s}$ is equal to

(a)	$[\begin{matrix} - j 5.4 & - j 0.34 & j 3.33 \\ j 0.34 & - j 4.22 & j 2.5 \\ j 3.33 & j 2.5 & - j 5.833 \end{matrix}]$
(b)	$[\begin{matrix} j 2.2 & j 3 \\ j 3 & j 3.4 \end{matrix}]$
(c)	$[\begin{matrix} j 1.1 & j 2 & j 3 \\ j 3 & j 4 & j 5 \\ j 3 & j 5 & j 6 \end{matrix}]$
(d)	None of above

Showing 11 to 20 out of 30 Questions