MCQs of Impact of Jet and Hydraulic Turbines (Fluid Mechanics and Hydraulic Machines - 3141906)

Fluid Mechanics and Hydraulic Machines (3141906) MCQs

MCQs of Impact of Jet and Hydraulic Turbines

Showing 1 to 10 out of 30 Questions

The force exerted (in newton) by a jet of water impinging normally on a fixed plate is

(a)	$\frac{ρ a V}{2}$
(b)	$ρ a V$
(c)	$\frac{ρ a V^{2}}{2}$
(d)	$ρ a V^{2}$

The force exerted by a jet of water (in a direction normal to flow) impinging on a fixed plate inclined at an angle θ with the jet is

(a)	$\frac{ρ a V}{2} \times \sin θ$
(b)	$ρ a V \times \sin θ$
(c)	$\frac{ρ a V^{2}}{2} \times \sin 2 θ$
(d)	$ρ a V^{2} \times \sin θ$

The force exerted by a jet of water impinging normally on a plate which due to the impact of jet, moves in the direction of jet with velocity u is

(a)	$\frac{ρ a (V - u)}{2}$
(b)	$ρ a (V - u)$
(c)	$\frac{ρ a {(V - u)}^{2}}{2}$
(d)	$ρ a {(V - u)}^{2}$

The ration of the normal force of a jet of water on a plane inclined at an angle of 30° as compared to that when the plate is normal to jet, is

(a)	$\frac{1}{\sqrt{2}}$
(b)	$\frac{1}{2}$
(c)	$1$
(d)	$\sqrt{2}$

A jet of water is striking at the centre of a curved vane moving with a uniform velocity in the direction of the jet. For the maximum efficiency, the vane velocity is …………. of the jet velocity.

(a)	one-half
(b)	one-third
(c)	two-third
(d)	three-fourth

Braking jet in an impulse turbine is used

(a)	to break the jet of water
(b)	to bring the runner to rest in a short time
(c)	to change the direction of runner
(d)	none of these

A Pelton wheel is

(a)	tangential flow impulse turbine
(b)	inward flow impulse turbine
(c)	outward flow impulse turbine
(d)	outward flow impulse turbine

An impulse turbine is used for

(a)	Low head of water
(b)	High head of water
(c)	Medium head of water
(d)	High discharge

The gross or total head of the turbine is the ………….. of the water levels at the head race and tail race.

(a)	sum
(b)	difference
(c)	product
(d)	division

10.

H_{g}

is the gross or total head and

h_{f}

is the head lost due to friction, then net or effective head (H) is given by

(a)	$H = \frac{H_{g}}{h_{f}}$
(b)	$H = H_{g} \times h_{f}$
(c)	$H = H_{g} + h_{f}$
(d)	$H = H_{g} - h_{f}$

Showing 1 to 10 out of 30 Questions