Design of Structures (3150612) MCQs

MCQs of Limit state design of Steel components

Showing 61 to 70 out of 129 Questions
61.

What is stress concentration factor?

(a)

Ratio of average stress to maximum elastic stress

(b)

Product of average stress and maximum elastic stress

(c)

Ratio of maximum elastic stress to average stress

(d)

Twice the average stress

Answer:

Option (c)

62.

What is block shear failure?

(a)

Failure of fasteners occurs along path involving tension on one plane and shear on perpendicular plane along fasteners

(b)

Failure of member occurs along path involving tension on one plane and shear on perpendicular plane along fasteners

(c)

Failure of member occurs along path involving tension on one plane and shear on parallel plane along fasteners

(d)

Failure of fasteners occurs along path involving tension on one plane and shear on parallel plane along fasteners

Answer:

Option (b)

63.

The possibility of block shear failure increases by

(a)

Larger connection length

(b)

Increasing the number of bolts per connection

(c)

With use of low strength bolts

(d)

With use of high bearing strength material

Answer:

Option (d)

64.

The design strength of tension member corresponding to gross section yielding is given by :

(a)

ƳmofyAg

(b)

ƳmofyAg

(c)

fyAgƳmo

(d)

fyAgƳmo

Answer:

Option (d)

65.

Which of the following relation is correct?

(a)

Net area = Gross area x Hole diameter

(b)

Net area = Gross area + Hole diameter

(c)

Net area = Gross area – Hole diameter

(d)

Net area = Gross area / Hole diameter

Answer:

Option (c)

66.

The block shear strength of connection is ________

(a)

Block shear strength at an end connection for shear fracture and tension yield

(b)

Block shear strength at an end connection for shear yield and tension fracture

(c)

Larger of block shear strength at an end connection for (shear fracture, tension yield) and (shear yield, tension fracture

(d)

Smaller of block shear strength at an end connection for (shear fracture, tension yield) and (shear yield, tension fracture

Answer:

Option (d)

67.

The design strength of tension member corresponding to net section rupture is given by :

(a)

AnfyƳm1

(b)

0.9AnfyƳm1

(c)

 0.9AnfyƳm1

(d)

 0.9AnfyƳm1

Answer:

Option (d)

68.

The block shear strength at an end connection for shear yield and tension fracture is given by :

(a)

Avgfy3Ƴmo + 0.9AtnfuƳm1

(b)

Atgfy3Ƴmo + 0.9AvnfuƳm1

(c)

0.9Atgfy3Ƴmo + AvnfuƳm1

(d)

0.9Avgfy3Ƴmo + AtnfuƳm1

Answer:

Option (a)

69.

The block shear strength at an end connection for shear fracture and tension yield is given by :

(a)

Avgfy3Ƴmo + 0.9AtnfuƳm1

(b)

Atgfy3Ƴmo + 0.9Avnfu3Ƴm1

(c)

0.9Avgfy3Ƴmo + AtnfuƳm1

(d)

0.9Atgfy3Ƴmo + AvnfuƳm1

Answer:

Option (b)

70.

The design tensile strength of tensile member is

(a)

Minimum of strength due to gross yielding, net section rupture, block shear

(b)

Maximum of strength due to gross yielding, net section rupture, block shear

(c)

Strength due to gross yielding

(d)

Strength due to block shear

Answer:

Option (a)

Showing 61 to 70 out of 129 Questions