Dynamics of Machinery (3151911) MCQs

MCQs of Balancing of Reciprocating Masses

Showing 41 to 49 out of 49 Questions
41.

When the primary direct crank of a reciprocating engine makes an angle θ with the line of stroke, then the secondary direct crank will make an angle of ________ with the line of stroke.

(a)

θ/2 

(b)

θ

(c)

(d)

Answer:

Option (c)

42.

For the secondary balancing of the engine, which of the condition is necessary?

(a)

Secondary force polygon must be close

(b)

Secondary force polygon must be open

(c)

Primary force polygon must be close

(d)

Primary force polygon must be open

Answer:

Option (a)

43.

Which of the following statement is correct?

(a)

In any engine, 100% of the reciprocating masses can be balanced dynamically

(b)

In the case of balancing of the multicylinder engine, the value of secondary force is higher than the value of the primary force

(c)

In the case of balancing of multi mass rotating systems, dynamic balancing can be directly started without static balancing done to the system

(d)

none of these

Answer:

Option (c)

44.

In a multicylinder inline engine, each imaginary secondary crank with a mass attached to the crankpin is inclined to the line of a stroke at which angle?

(a)

Twice the angle of the crank

(b)

Half the angle of the crank

(c)

Thrice the angle of the crank

(d)

Four times the angle of the crank

Answer:

Option (a)

45.

Length of the crank shaft is maximum in

(a)

V-type engine

(b)

inline engine

(c)

radial engine

(d)

opposite cylinder engine

Answer:

Option (b)

46.

The resultant primary unbalanced force due to inertia of reciprocating parts in a V-engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of the crank, and  = Angle of inclination of the crank with the line of stroke

(a)

2mrω2cos2α cosθ2 +sin2α sinθ2

(b)

2mrω2cos2α cosθ2 -sin2α sinθ2

(c)

2mrω2cos2θ cosα2 +sin2θ sinα2

(d)

2mrω2cos2θ cosα2 -sin2θ sinα2

Answer:

Option (a)

47.

The resultant secondary unbalanced force due to inertia of reciprocating parts in a V-engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank,  = Angle of inclination of the crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of the crank)

(a)

mrω24ncosα cos2α cos2θ2 +sinα sin2α sin2θ2

(b)

mrω22ncosα cos2α cos2θ2 +sinα sin2α sin2θ2

(c)

2mrω2ncosα cos2α cos2θ2 +sinα sin2α sin2θ2

(d)

mrω2ncosα cos2α cos2θ2 +sinα sin2α sin2θ2

Answer:

Option (c)

48.

The maximum secondary unbalanced force due to inertia of reciprocating parts in a V-engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank,  = Angle of inclination of the crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of the crank)

(a)

mrω2nsin2θ

(b)

2mrω2nsin2θ

(c)

2mrω2nsin2θ

(d)

mrω22nsin2θ

Answer:

Option (b)

49.

The V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 11.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of the maximum resultant secondary force in Newtons?

(a)

736

(b)

836

(c)

936

(d)

636

Answer:

Option (b)

Showing 41 to 49 out of 49 Questions