Machine Design (2171909) MCQs

MCQs of Gear Design

Showing 61 to 60 out of 70 Questions
61.

In worm gears, the sum of the helix angle and lead angle is ______.

(a)

30°

(b)

45°

(c)

60°

(d)

90°

Answer:

Option (d)

62.

The efficiency of worm gears can be given by ______.

(a)

η=μ cosα-tanγμ cosα+cotγ

(b)

η=μ cosα+tanγμ cosα-cotγ

(c)

η=cosα-μ tanγcosα+μ cotγ

(d)

η=cosα+μ tanγcosα-μ cotγ

Answer:

Option (c)

63.

When bevel gears having equal teeth and equal pitch angles connect two shafts whose axes intersect at the right angle, then they are known as ______.

(a)

angular bevel gears

(b)

crown bevel gears

(c)

internal bevel gears

(d)

mitre gears

Answer:

Option (d)

64.

The face angle of a bevel gear is equal to _______.

(a)

pitch angle – addendum angle

(b)

pitch angle + addendum angle

(c)

pitch angle – dedendum angle

(d)

pitch angle + dedendum angle

Answer:

Option (b)

65.

The root angle of a bevel gear is equal to ______.

(a)

pitch angle – addendum angle

(b)

pitch angle + addendum angle

(c)

pitch angle – dedendum angle

(d)

pitch angle + dedendum angle

Answer:

Option (c)

66.

If b denotes the face width and L denotes the cone distance, then the bevel factor is written as _______.

(a)

bL

(b)

b2L

(c)

1 - 2bL

(d)

1-bL

Answer:

Option (d)

67.

In worm gears, the angle between the tangent to the thread helix on the pitch cylinder and the plane normal to the axis of the worm is called _______.

(a)

pressure angle

(b)

lead angle

(c)

helix angle

(d)

friction angle

Answer:

Option (b)

68.

The number of starts on the worm for a velocity ratio of 40 should be __________.

(a)

single

(b)

double

(c)

triple

(d)

quadruple

Answer:

Option (a)

69.

If P is power transmitted (in watts) and η is the efficiency of the worm gearing, then power lost in friction (in watts) is given by _________.

(a)

Qg=η-1P

(b)

Qg=1-ηP

(c)

Qg=η-1×P

(d)

Qg=1-η×P

Answer:

Option (d)

70.

The heat-dissipating capacity of a worm drive can be given by ________.

(a)

Qd=A×t2-t1×K

(b)

Qd=A×Kt2-t1

(c)

Qd=A×t2-t1K

(d)

Qd=K×t2-t1A

Answer:

Option (a)

Showing 61 to 60 out of 70 Questions