Railway and Airport Engineering (3170619) MCQs

MCQs of Unit 1 : Geometric design of railway track

Showing 11 to 20 out of 41 Questions
11.
When a train travels around a curve at a speed lower than the equilibrium speed is known as
(a) Cant excess
(b) Cant deficiency
(c) Cant
(d) None
Answer:

Option (a)

12.
The condition for equilibrium superelevation
(a) 𝑒/𝐺=𝐹/𝑊
(b) 𝑒/𝐺=W/F
(c) G/e=𝐹/𝑊
(d) e=F*W/G
Answer:

Option (a)

13.
where e is the equilibrium superelevation, G is the gauge, V is the velocity, g is the acceleration due to gravity, and R is the radius of the curve. In the metric system equilibrium superelevation is given by the formula
(a) e= (GV^2)/(127*R)
(b) e= (GV^3)/(127*R)
(c) e= (GV)/(127*R)
(d) e= (GV^2)/(9.81*R)
Answer:

Option (a)

14.
Maximum value of cant on BG track for A,B and C group railway track
(a) 90 mm
(b) 165 mm
(c) 160 mm
(d) 140 mm
Answer:

Option (b)

15.
Maximum value of cant on NG track under normal condition
(a) 165 mm
(b) 110 mm
(c) 140 mm
(d) 90 mm
Answer:

Option (d)

16.
The maximum cant deficiency and cant excess can be provided in IR Track
(a) 75 mm
(b) 65 mm
(c) 90 mm
(d) 110 mm
Answer:

Option (a)

17.
Calculate equilibrium superelevation for BG track having radius of curve 550 m and speed 80 KMPH nearest to
(a) 155 mm
(b) 165 mm
(c) 140 mm
(d) 90 mm
Answer:

Option (a)

18.
Calculate Radius for 8 degree of curve considering chord length 30 m
(a) 205 m
(b) 255 m
(c) 215 m
(d) 219 m
Answer:

Option (c)

19.
Calculate Radius for 8 degree of curve considering chord length 30.5 m , nearest to
(a) 205 m
(b) 219 m
(c) 291 m
(d) none
Answer:

Option (b)

20.
A 5˚ curve diverges from main line of 4˚ curve in an opposite direction in the layout of a broad gauge yard. If the permissible speed on the main curve is 54.33 kmph, determine the speed restriction on the branch line nearest to. Assume permissible cant deficiency as 7.5 cm.
(a) 50 KMPH
(b) 40 KMPH
(c) 60 KMPH
(d) 65 KMPH
Answer:

Option (b)

Showing 11 to 20 out of 41 Questions