| 31. |
An exception may be generated due to ___________
exception જનરેટ થવાના કારણો _________
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Answer:
Option (a) |
| 32. |
There can be a try block without catch block but vice versa is not possible
catch બ્લોક વગર try બ્લોક હોઈ શકે છે પરંતુ તેનાથી ઉલટું શક્ય છે કે નહિ ?
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Answer:
Option (a) |
| 33. |
How many catch block can a single try block can have ?
એક try બ્લોક માં કેટલા catch બ્લોક હોઈ શકે છે ?
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Answer:
Option (d) |
| 34. |
Finally block is executed ________
Finally બ્લોક એક્ષીક્યુટ ક્યારે થશે ?
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Answer:
Option (d) |
| 35. |
Guess the output of the following code;
Module Program
Sub Main(args As String())
Dim a As Integer = 1
Dim b As Integer = 10 / a
Try
If a = 1 Then
a = 10 / (a - a)
End If
Catch e As OverflowException
Console.Write("B")
Finally
Console.Write("A")
End Try
Console.ReadLine()
End Sub
End Module
નીચેના પ્રોગ્રામ નું આઉટપુટ જણાવો;
Module Program
Sub Main(args As String())
Dim a As Integer = 1
Dim b As Integer = 10 / a
Try
If a = 1 Then
a = 10 / (a - a)
End If
Catch e As OverflowException
Console.Write("B")
Finally
Console.Write("A")
End Try
Console.ReadLine()
End Sub
End Module
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Answer:
Option (c) |
| 36. |
________________ statement is used to handle unstructured exception handling
______ સ્ટેટમેન્ટ નો ઉપયોગ unstructured exception હેન્ડલ કરવા માટે થાય છે
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Answer:
Option (a) |
| 37. |
Guess the output of the following code;
Module Program
Sub Main(args As String())
On Error GoTo Handler
Dim a As Integer = 0
Dim b As Integer = 156
Dim ans As Integer
ans = b / a
Console.WriteLine("Press Enter to continue...")
Console.ReadLine()
Handler:
Console.WriteLine("Exception Generated...")
End Sub
End Module
નીચેના પ્રોગ્રામ નું આઉટપુટ જણાવો;
Module Program
Sub Main(args As String())
On Error GoTo Handler
Dim a As Integer = 0
Dim b As Integer = 156
Dim ans As Integer
ans = b / a
Console.WriteLine("Press Enter to continue...")
Console.ReadLine()
Handler:
Console.WriteLine("Exception Generated...")
End Sub
End Module
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Answer:
Option (b) |
| 38. |
Guess the output of the following code;
Module Program
Sub Main(args As String())
On Error GoTo Handler
Dim a As Integer = 0
Dim b As Integer = 156
Dim ans As Integer
ans = b / a
Console.WriteLine("Press Enter to continue...")
Exit Sub
Handler:
Console.WriteLine("Exception Generated...")
Resume Next
End Sub
End Module
નીચેના પ્રોગ્રામ નું આઉટપુટ જણાવો;
Module Program
Sub Main(args As String())
On Error GoTo Handler
Dim a As Integer = 0
Dim b As Integer = 156
Dim ans As Integer
ans = b / a
Console.WriteLine("Press Enter to continue...")
Exit Sub
Handler:
Console.WriteLine("Exception Generated...")
Resume Next
End Sub
End Module
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|
Answer:
Option (d) |
| 39. |
MDI Stands for _____
MDI મતલબ _____
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|
Answer:
Option (c) |
| 40. |
In the following code 'Me' indicates to which control ?
Dim ChildForm As Form1 = New Form1() ChildForm.MdiParent = Me ChildForm.WindowState = FormWindowState.Normal ChildForm.Show()
નીચે દર્શાવેલ પ્રોગામ માં 'Me' ક્યાં કંટ્રોલ ને દર્શાવે છે ?
Dim ChildForm As Form1 = New Form1() ChildForm.MdiParent = Me ChildForm.WindowState = FormWindowState.Normal ChildForm.Show()
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Answer:
Option (b) |